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Synthesis and single crystal structures of first examples of tridentate ligands of (Te, N, S) type and their complexes with palladium(II), platinum(II) and ruthenium(II)

Authors
Journal
Inorganica Chimica Acta
0020-1693
Publisher
Elsevier
Publication Date
Volume
361
Issue
5
Identifiers
DOI: 10.1016/j.ica.2007.09.012
Keywords
  • Tellurated Schiff Bases
  • (Te
  • N
  • S) Ligands
  • Platinum
  • Palladium
  • Ruthenium
  • Metal Complex
  • Synthesis
  • Single Crystal Structure
  • X-Ray Diffraction
Disciplines
  • Mathematics

Abstract

Abstract The First examples of (Te, N, S) type ligands, 2-CH 3SC 6H 4CH NCH 2CH 2TeC 6H 4-4-OCH 3 ( L 1) and 2- CH 3SC 6H 4CHNHCH 2CH 2TeC 6H 4-4-OCH 3 ( L 2), and their metal complexes, [PdCl( L 1)]PF 6 · CHCl 3 · 0.5H 2O ( 4), [PtCl( L 1)]PF 6 ( 5), [PdCl( L 2)]ClO 4.CHCl 3 ( 6), [PtCl( L 2)]ClO 4 ( 7), and [Ru( p-cymene)( L 2)](PF 6) 2 · CHCl 3 ( 8), have been synthesized and characterized. The single crystal structures of 4, 6 and 8 have revealed that both the ligands coordinate in them in a tridentate (Te, N, S) mode. The geometry around Pd in both the complexes has been found to be square planar, whereas for Ru in a half sandwich complex 8, it is found to be octahedral. Between two molecules of 4 there are intra and inter molecular weak Te⋯Cl [3.334(3) and 3.500(3) Å, respectively] interactions along with weak intermolecular Pd⋯Te [3.621(2) Å] interactions. The Pd–Te bond lengths are between 2.517(6) and 2.541(25) Å and the Ru–Te bond length is 2.630(6) Å. The crystal structure of [PdCl 2(4-MeO–C 6H 4– TeCH 2CH 2NH 2)] ( 9) is also determined. It is formed when KPF 6 is not added in the synthesis of 4 and Pd-complex of L 1 is recrystallized. Apart from Te⋯Cl secondary interactions, C–H⋯π interactions also exist in the crystal of 9.

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